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3.14x^2=40
We move all terms to the left:
3.14x^2-(40)=0
a = 3.14; b = 0; c = -40;
Δ = b2-4ac
Δ = 02-4·3.14·(-40)
Δ = 502.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{502.4}}{2*3.14}=\frac{0-\sqrt{502.4}}{6.28} =-\frac{\sqrt{}}{6.28} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{502.4}}{2*3.14}=\frac{0+\sqrt{502.4}}{6.28} =\frac{\sqrt{}}{6.28} $
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